What is the d/(dt)(2sin(t)-sin(2t)) ?

The d/(dt)(2sin(t)-sin(2t)) is 2cos(t)-cos(2t)*2

What is the first d/(dt)(2sin(t)-sin(2t)) ?

The first d/(dt)(2sin(t)-sin(2t)) is 2cos(t)-cos(2t)*2

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\frac{d}{d t} (2 sin (t) - sin (2 t))

2 cos (t) - cos (2 t) \cdot 2

Solution steps

\frac{d}{d t} (2 sin (t) - sin (2 t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (2 sin (t)) - \frac{d}{d t} (sin (2 t))

\frac{d}{d t} (2 sin (t)) = 2 cos (t)

\frac{d}{d t} (sin (2 t)) = cos (2 t) \cdot 2

= 2 cos (t) - cos (2 t) \cdot 2

\int (6 x - 1) d x

5 x, 9 x^{2}

x^{2} y^{^{''}} - 6 y = x^{4}

\frac{\partial}{\partial y} (x - 2 y + 2 z)

\frac{d}{d t} (\frac{t - t}{t ^{\frac{1}{9}}})

What is the d/(dt)(2sin(t)-sin(2t)) ?
The d/(dt)(2sin(t)-sin(2t)) is 2cos(t)-cos(2t)*2
What is the first d/(dt)(2sin(t)-sin(2t)) ?
The first d/(dt)(2sin(t)-sin(2t)) is 2cos(t)-cos(2t)*2