What is the solution for x^2y^{''}-6y=x^4 ?

The solution for x^2y^{''}-6y=x^4 is y=c_{1}x^3+(c_{2}}{x^2}+\frac{x^4)/6

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x^2y^{''}-6y=x^4

x^{2} y^{^{''}} - 6 y = x^{4}

y = c_{1} x^{3} + \frac{c _{2}}{x ^{2}} + \frac{x ^{4}}{6}

Solution steps

x^{2} y^{''} (x) - 6 y = x^{4}

Solve linear ODE:

y = c_{1} x^{3} + \frac{c _{2}}{x ^{2}} + \frac{x ^{4}}{6}

y = c_{1} x^{3} + \frac{c _{2}}{x ^{2}} + \frac{x ^{4}}{6}

\frac{\partial}{\partial y} (x - 2 y + 2 z)

\frac{d}{d t} (\frac{t - t}{t ^{\frac{1}{9}}})

\frac{\partial}{\partial y} (2 cos (y))

\int 2 e^{θ} d θ

(\frac{1}{x ^{2}} - \frac{3}{x ^{4}}) (x + 5 x^{3})

What is the solution for x^2y^{''}-6y=x^4 ?
The solution for x^2y^{''}-6y=x^4 is y=c_{1}x^3+(c_{2}}{x^2}+\frac{x^4)/6