What is the derivative of 2/((x-2^2)) ?

The derivative of 2/((x-2^2)) is -4/((x-2)^3)

What is the first derivative of 2/((x-2^2)) ?

The first derivative of 2/((x-2^2)) is -4/((x-2)^3)

Popular >

\frac{d}{d x} (\frac{2}{( x - 2 ) ^{2}})

- \frac{4}{( x - 2 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{2}{( x - 2 ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{( x - 2 ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} ((x - 2)^{- 2})

Apply the chain rule:

- \frac{2}{( x - 2 ) ^{3}} \frac{d}{d x} (x - 2)

= - \frac{2}{( x - 2 ) ^{3}} \frac{d}{d x} (x - 2)

\frac{d}{d x} (x - 2) = 1

= 2 (- \frac{2}{( x - 2 ) ^{3}} \cdot 1)

Simplify

2 (- \frac{2}{( x - 2 ) ^{3}} \cdot 1) : - \frac{4}{( x - 2 ) ^{3}}

= - \frac{4}{( x - 2 ) ^{3}}

\int \frac{4 x ^{3} - x ^{2} + 2}{x ^{4} - x ^{3} + x ^{2}} d x

4 x^{2} \frac{d y}{d x} = \frac{d y}{d x} + 4 x e^{- y}

\int_{0}^{1} π (y - y^{4}) d y

\int \frac{4 x + 6}{( x ^{2} + 3 x + 7 ) ^{3}} d x

\frac{x ^{5}}{8}

What is the derivative of 2/((x-2^2)) ?
The derivative of 2/((x-2^2)) is -4/((x-2)^3)
What is the first derivative of 2/((x-2^2)) ?
The first derivative of 2/((x-2^2)) is -4/((x-2)^3)