What is the derivative of sin(2pi(1-x)) ?

The derivative of sin(2pi(1-x)) is -2picos(2pi(1-x))

What is the first derivative of sin(2pi(1-x)) ?

The first derivative of sin(2pi(1-x)) is -2picos(2pi(1-x))

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\frac{d}{d x} (sin (2 π (1 - x)))

- 2 π cos (2 π (1 - x))

Solution steps

\frac{d}{d x} (sin (2 π (1 - x)))

Apply the chain rule:

cos (2 π (1 - x)) \frac{d}{d x} (2 π (1 - x))

= cos (2 π (1 - x)) \frac{d}{d x} (2 π (1 - x))

\frac{d}{d x} (2 π (1 - x)) = - 2 π

= cos (2 π (1 - x)) (- 2 π)

Simplify

= - 2 π cos (2 π (1 - x))

\int \frac{cos ( t )}{7 + sin ( t )} d t

y = x^{2} + 10 x + 25, y = 7 x + 35

\int \frac{1}{( 1 + x ) ( 1 - x )} d x

\frac{1}{x - 9}

\frac{d}{d x} (\frac{1 - 6 x}{5 + x})

What is the derivative of sin(2pi(1-x)) ?
The derivative of sin(2pi(1-x)) is -2picos(2pi(1-x))
What is the first derivative of sin(2pi(1-x)) ?
The first derivative of sin(2pi(1-x)) is -2picos(2pi(1-x))