What is area y=x^2+10x+25,y=7x+35 ?

The answer to area y=x^2+10x+25,y=7x+35 is 343/6

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area y=x^2+10x+25,y=7x+35

area

y = x^{2} + 10 x + 25, y = 7 x + 35

\frac{343}{6}

Decimal Notation

57.16666 \dots

Solution steps

Apply the area formula:

\int_{- 5}^{2} x^{2} + 10 x + 25 - (7 x + 35) d x

Solve

\int_{- 5}^{2} x^{2} + 10 x + 25 - (7 x + 35) d x : \frac{343}{6}

The area is:

= \frac{343}{6}

\int \frac{1}{( 1 + x ) ( 1 - x )} d x

\frac{1}{x - 9}

\frac{d}{d x} (\frac{1 - 6 x}{5 + x})

\int \frac{1}{8 - x} d x

\frac{d}{d x} (7 x + 8)

What is area y=x^2+10x+25,y=7x+35 ?
The answer to area y=x^2+10x+25,y=7x+35 is 343/6