What is the first derivative of 7x+8 ?

The first derivative of 7x+8 is 7

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derivative of 7x+8

\frac{d}{d x} (7 x + 8)

7

Solution steps

\frac{d}{d x} (7 x + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (7 x) + \frac{d}{d x} (8)

\frac{d}{d x} (7 x) = 7

\frac{d}{d x} (8) = 0

= 7 + 0

Simplify

= 7

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