What is the sum from n=0 to infinity of (n/(n+3))^n ?

The sum from n=0 to infinity of (n/(n+3))^n is diverges

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sum from n=0 to infinity of (n/(n+3))^n

n = 0 \sum \infty (\frac{n}{n + 3})^{n}

diverges

Solution steps

n = 1 \sum \infty (\frac{n}{n + 3})^{n}

Apply Series Divergence Test:

diverges

= diverges

x \to 1 lim (4 x - 2)

2 sin (x) cos (x)

\frac{d y}{d x} = y, y (7) = 8

\frac{\partial}{\partial y} (sin (3 x) cos (3 y))

\frac{( e ^{\frac{b}{x}} )}{( e ^{\frac{b}{x}} - 1 )}

What is the sum from n=0 to infinity of (n/(n+3))^n ?
The sum from n=0 to infinity of (n/(n+3))^n is diverges