What is the d/(dt)((sec^2(t))/(sec(t)tan(t))) ?

The d/(dt)((sec^2(t))/(sec(t)tan(t))) is -cot(t)csc(t)

What is the first d/(dt)((sec^2(t))/(sec(t)tan(t))) ?

The first d/(dt)((sec^2(t))/(sec(t)tan(t))) is -cot(t)csc(t)

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\frac{d}{d t} (\frac{sec ^{2} ( t )}{sec ( t ) tan ( t )})

- cot (t) csc (t)

Solution steps

\frac{d}{d t} (\frac{sec ^{2} ( t )}{sec ( t ) tan ( t )})

Simplify

\frac{sec ^{2} ( t )}{sec ( t ) tan ( t )} : csc (t)

= \frac{d}{d t} (csc (t))

Apply the common derivative:

\frac{d}{d t} (csc (t)) = - cot (t) csc (t)

= - cot (t) csc (t)

\int_{- 2}^{1} \frac{1}{x ^{4}} d x

\frac{\partial}{\partial x} (2 y^{2} + 3 x)

\int \frac{x ^{10}}{x ^{2} + x - 2} d x

\int \frac{x ^{2}}{( x ^{3} - 2 ) ^{3}} d x

\frac{d}{d x} (\frac{8 x ^{2} + 4 x + 8}{x})

What is the d/(dt)((sec^2(t))/(sec(t)tan(t))) ?
The d/(dt)((sec^2(t))/(sec(t)tan(t))) is -cot(t)csc(t)
What is the first d/(dt)((sec^2(t))/(sec(t)tan(t))) ?
The first d/(dt)((sec^2(t))/(sec(t)tan(t))) is -cot(t)csc(t)