What is the derivative of 2x-x^3 ?

The derivative of 2x-x^3 is 2-3x^2

What is the first derivative of 2x-x^3 ?

The first derivative of 2x-x^3 is 2-3x^2

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\frac{d}{d x} (2 x - x^{3})

2 - 3 x^{2}

Solution steps

\frac{d}{d x} (2 x - x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) - \frac{d}{d x} (x^{3})

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (x^{3}) = 3 x^{2}

= 2 - 3 x^{2}

\frac{d}{d x} (x^{2} + y^{2} + z^{2} + x y)

x y^{2} + 3 y^{2} - x^{2} y^{^{'}} = 0

\frac{d}{d x} (\frac{3 x - 2}{2 x - 3})

\int \frac{1}{t ^{\frac{3}{2}}} d t

\int \frac{2}{1 + 4 x ^{2}} d x

What is the derivative of 2x-x^3 ?
The derivative of 2x-x^3 is 2-3x^2
What is the first derivative of 2x-x^3 ?
The first derivative of 2x-x^3 is 2-3x^2