What is the derivative of y=2cos(x+y) ?

The derivative of y=2cos(x+y) is -2sin(x+y)

What is the first derivative of y=2cos(x+y) ?

The first derivative of y=2cos(x+y) is -2sin(x+y)

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derivative of

y = 2 cos (x + y)

- 2 sin (x + y)

Solution steps

\frac{d}{d x} (2 cos (x + y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (cos (x + y))

Apply the chain rule:

- sin (x + y) \frac{d}{d x} (x + y)

= - sin (x + y) \frac{d}{d x} (x + y)

\frac{d}{d x} (x + y) = 1

= 2 (- sin (x + y) \cdot 1)

Simplify

= - 2 sin (x + y)

\frac{d ^{2}}{d x ^{2}} (x^{2} - y^{2})

\frac{d}{d x} (y z (x)^{3})

\frac{\partial}{\partial y} (0)

\frac{d}{d x} (2 e^{2 x} \cdot x)

\int sin (x) + 6 d x

What is the derivative of y=2cos(x+y) ?
The derivative of y=2cos(x+y) is -2sin(x+y)
What is the first derivative of y=2cos(x+y) ?
The first derivative of y=2cos(x+y) is -2sin(x+y)