What is (\partial)/(\partial x)(e^{-2x}sin(y)) ?

The answer to (\partial)/(\partial x)(e^{-2x}sin(y)) is -2e^{-2x}sin(y)

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(\partial)/(\partial x)(e^{-2x}sin(y))

\frac{\partial}{\partial x} (e^{- 2 x} sin (y))

- 2 e^{- 2 x} sin (y)

Solution steps

\frac{\partial}{\partial x} (e^{- 2 x} sin (y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sin (y) \frac{\partial}{\partial x} (e^{- 2 x})

Apply the chain rule:

e^{- 2 x} \frac{\partial}{\partial x} (- 2 x)

= e^{- 2 x} \frac{\partial}{\partial x} (- 2 x)

\frac{\partial}{\partial x} (- 2 x) = - 2

= sin (y) e^{- 2 x} (- 2)

Simplify

= - 2 e^{- 2 x} sin (y)

n = 1 \sum \infty \frac{n ^{4}}{4 ^{n}}

x, \frac{1}{x ^{2}}, [0, 1]

\frac{d}{d x} (ln ((1 - x^{2})^{- \frac{1}{2}}))

\frac{1}{1 + s ^{2}}

\int 8 t^{3} - 6 t^{- 2} d t

What is (\partial)/(\partial x)(e^{-2x}sin(y)) ?
The answer to (\partial)/(\partial x)(e^{-2x}sin(y)) is -2e^{-2x}sin(y)