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Popular >

y^'=2x-y,y(0)=1

Solution

y^{^{'}} = 2 x - y, y (0) = 1

Solution

y = 2 (x - 1) + \frac{3}{e ^{x}}

Solution steps

y^{'} (x) = 2 x - y

Solve linear ODE:

y = 2 (x - 1) + \frac{3}{e ^{x}}

y = 2 (x - 1) + \frac{3}{e ^{x}}

Popular Examples

y^'=sqrt(x^9+1)

y^{^{'}} = x^{9} + 1

derivative of h(t)=t^2(7t+8)^3 derivative of

h (t) = t^{2} (7 t + 8)^{3}

(d^2)/(dx^2)(7sec(x))

\frac{d ^{2}}{d x ^{2}} (7 sec (x))

(\partial)/(\partial x)(((2+t^2))/(3x-x^3))

\frac{\partial}{\partial x} (\frac{( 2 + t ^{2} )}{3 x - x ^{3}})

derivative of y=e^{2-x}derivative of

y = e^{2 - x}

Frequently Asked Questions (FAQ)

What is the solution for y^'=2x-y,y(0)=1 ?
The solution for y^'=2x-y,y(0)=1 is y=2(x-1)+3/(e^x)