What is the solution for (dx)/(dt)-2x=x^3 ?

The solution for (dx)/(dt)-2x=x^3 is x=sqrt(2/(e^{-4t-c_{1))-1}},x=-sqrt(2/(e^{-4t-c_{1))-1}}

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(dx)/(dt)-2x=x^3

\frac{d x}{d t} - 2 x = x^{3}

x = \frac{2}{e ^{- 4 t - c_{1}} - 1}, x = - \frac{2}{e ^{- 4 t - c_{1}} - 1}

Solution steps

\frac{d x}{d t} - 2 x = x^{3}

Solve Bernoulli ODE:

x = \frac{2}{e ^{- 4 t - c_{1}} - 1}, x = - \frac{2}{e ^{- 4 t - c_{1}} - 1}

x = \frac{2}{e ^{- 4 t - c_{1}} - 1}, x = - \frac{2}{e ^{- 4 t - c_{1}} - 1}

\frac{d}{d x} (ln (x) - 2 x^{2})

\frac{d}{d x} (\frac{5 x}{x ^{2} + 1})

e^{y x^{2}}

\frac{d}{d x} ((3 x - 4)^{2})

\frac{d}{d x} (x (12 - 2 x)^{2})

What is the solution for (dx)/(dt)-2x=x^3 ?
The solution for (dx)/(dt)-2x=x^3 is x=sqrt(2/(e^{-4t-c_{1))-1}},x=-sqrt(2/(e^{-4t-c_{1))-1}}