What is the tangent of y=xsqrt(x),(4,8) ?

The tangent of y=xsqrt(x),(4,8) is y=3x-4

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tangent of y=xsqrt(x),(4,8)

tangent of

y = x x, (4, 8)

y = 3 x - 4

Solution steps

Find the slope of

y = x x : \frac{d y}{d x} = \frac{3 x}{2}

Compute the slope of

y = x x

(4, 8) : m = 3

Find the line with slope m=

3

and passing through

(4, 8) : y = 3 x - 4

y = 3 x - 4

\frac{\partial}{\partial t} (2 cos (t) + 8 x^{2})

\frac{d}{d x} (3 cos (x) - 2 e^{2 x})

f (x) = x^{3} - 2 x + 1, at x = - 1

(e^{x} - e^{- x}) \frac{d y}{d x} = y^{2}

\frac{\partial}{\partial x} (- 10 x + 7 y^{5})

What is the tangent of y=xsqrt(x),(4,8) ?
The tangent of y=xsqrt(x),(4,8) is y=3x-4