What is the solution for y^'-x^2=2x^2y ?

The solution for y^'-x^2=2x^2y is y=(e^{(2x^3+c_{1})/3})/(2)-1/2

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y^'-x^2=2x^2y

y^{^{'}} - x^{2} = 2 x^{2} y

y = \frac{e ^{\frac{2 x ^{3} + c _{1}}{3}}}{2} - \frac{1}{2}

Solution steps

y^{'} (x) - x^{2} = 2 x^{2} y

Solve separable ODE:

y = \frac{e ^{\frac{2 x ^{3} + c _{1}}{3}}}{2} - \frac{1}{2}

y = \frac{e ^{\frac{2 x ^{3} + c _{1}}{3}}}{2} - \frac{1}{2}

\frac{d}{d x} (\frac{x ^{2}}{10 + x})

18 x

f (x) = 5 x - 4 x^{2}, (- 2, - 26)

\int 3 x + 4 d x

\int sin^{2} (x) cos (x) d x

What is the solution for y^'-x^2=2x^2y ?
The solution for y^'-x^2=2x^2y is y=(e^{(2x^3+c_{1})/3})/(2)-1/2