What is the derivative of 1-|x-1| ?

The derivative of 1-|x-1| is -(x-1)/(|x-1|)

What is the first derivative of 1-|x-1| ?

The first derivative of 1-|x-1| is -(x-1)/(|x-1|)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (1 - ∣ x - 1 ∣)

- \frac{x - 1}{∣ x - 1 ∣}

Solution steps

\frac{d}{d x} (1 - ∣ x - 1 ∣)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (∣ x - 1 ∣)

\frac{d}{d x} (1) = 0

\frac{d}{d x} (∣ x - 1 ∣) = \frac{x - 1}{∣ x - 1 ∣}

= 0 - \frac{x - 1}{∣ x - 1 ∣}

Simplify

= - \frac{x - 1}{∣ x - 1 ∣}

\int_{- 1}^{1} (4 - 4 x^{2})^{2} d x

\frac{\partial}{\partial x} (tan (\frac{u}{v}))

\frac{d}{d x} ((x + y)^{2})

\int_{0}^{1} 1 + 9 x^{2} d x

\int - \frac{1}{cos ^{2} ( x )} d x

What is the derivative of 1-|x-1| ?
The derivative of 1-|x-1| is -(x-1)/(|x-1|)
What is the first derivative of 1-|x-1| ?
The first derivative of 1-|x-1| is -(x-1)/(|x-1|)