What is area x=-y,x=2y+3,y=-2,y=1 ?

The answer to area x=-y,x=2y+3,y=-2,y=1 is No Solution

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area x=-y,x=2y+3,y=-2,y=1

area

x = - y, x = 2 y + 3, y = - 2, y = 1

No Solution

Solution steps

Isolate

y

for

x = - y : y = - x

Isolate

y

for

x = 2 y + 3 : y = \frac{x - 3}{2}

f_{1} (x) = - x

f_{2} (x) = \frac{x - 3}{2}

To find the intersection points solve

f_{i} (x) = f_{j} (x)

- x = \frac{x - 3}{2} : x = 1

- x = - 2 : x = 2

- x = 1 : x = - 1

\frac{x - 3}{2} = - 2 : x = - 1

\frac{x - 3}{2} = 1 : x = 5

- 2 = 1 :

False

Curves not bounded

= No Solution

\frac{d}{d x} (x ln (3))

f (x) = x + 1

\frac{d x}{x ( y - 1 )} + \frac{d y}{y ( x + 2 )} = 0, y (1) = 1

11 x - 4 y x^{2} + 1 y^{^{'}} = 0, y (0) = 7

x \to 5 lim (\frac{4}{x - 5})

What is area x=-y,x=2y+3,y=-2,y=1 ?
The answer to area x=-y,x=2y+3,y=-2,y=1 is No Solution