What is the integral of cos(2x)-sin(x) ?

The integral of cos(2x)-sin(x) is 1/2 sin(2x)+cos(x)+C

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integral of cos(2x)-sin(x)

\int cos (2 x) - sin (x) d x

\frac{1}{2} sin (2 x) + cos (x) + C

Solution steps

\int cos (2 x) - sin (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int cos (2 x) d x - \int sin (x) d x

\int cos (2 x) d x = \frac{1}{2} sin (2 x)

\int sin (x) d x = - cos (x)

= \frac{1}{2} sin (2 x) - (- cos (x))

Simplify

= \frac{1}{2} sin (2 x) + cos (x)

Add a constant to the solution

= \frac{1}{2} sin (2 x) + cos (x) + C

\frac{2 s}{( s ^{2} + 25 )}

0.1 e^{0.5061 (t)}

\int \frac{( ln ^{2} ( x ) )}{x} d x

\frac{d}{d x} (e^{- 2 x} cos (3 x) + sin (3 x))

\int x e^{2 x} sin (3 x) d x

What is the integral of cos(2x)-sin(x) ?
The integral of cos(2x)-sin(x) is 1/2 sin(2x)+cos(x)+C