What is the derivative of sec^4(2x^2) ?

The derivative of sec^4(2x^2) is 2sec^4(2)x

What is the first derivative of sec^4(2x^2) ?

The first derivative of sec^4(2x^2) is 2sec^4(2)x

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\frac{d}{d x} (sec^{4} (2) x^{2})

2 sec^{4} (2) x

Solution steps

\frac{d}{d x} (sec^{4} (2) x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sec^{4} (2) \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= sec^{4} (2) \cdot 2 x^{2 - 1}

Simplify

= 2 sec^{4} (2) x

\frac{d}{d x} (n x^{n})

\frac{2 x ^{2} + 8 x + 4}{x}

\frac{d}{d x} (\frac{- cos ( x ) - 1}{x ^{3} + x ^{2}})

y = 1 + 4 x^{2} - 2 x^{3}

\frac{\partial}{\partial y} (x^{3} - x y^{2} + 3 y^{2})

What is the derivative of sec^4(2x^2) ?
The derivative of sec^4(2x^2) is 2sec^4(2)x
What is the first derivative of sec^4(2x^2) ?
The first derivative of sec^4(2x^2) is 2sec^4(2)x