What is the derivative of nx^n ?

The derivative of nx^n is n^2x^{n-1}

What is the first derivative of nx^n ?

The first derivative of nx^n is n^2x^{n-1}

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\frac{d}{d x} (n x^{n})

n^{2} x^{n - 1}

Solution steps

\frac{d}{d x} (n x^{n})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= n \frac{d}{d x} (x^{n})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= nn x^{n - 1}

Simplify

nn x^{n - 1} : n^{2} x^{n - 1}

= n^{2} x^{n - 1}

\frac{2 x ^{2} + 8 x + 4}{x}

\frac{d}{d x} (\frac{- cos ( x ) - 1}{x ^{3} + x ^{2}})

y = 1 + 4 x^{2} - 2 x^{3}

\frac{\partial}{\partial y} (x^{3} - x y^{2} + 3 y^{2})

y = 4 x^{3} - 2 x, (1, 2)

What is the derivative of nx^n ?
The derivative of nx^n is n^2x^{n-1}
What is the first derivative of nx^n ?
The first derivative of nx^n is n^2x^{n-1}