What is the derivative of f(x)=2x^3+x ?

The derivative of f(x)=2x^3+x is 6x^2+1

What is the first derivative of f(x)=2x^3+x ?

The first derivative of f(x)=2x^3+x is 6x^2+1

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derivative of

f (x) = 2 x^{3} + x

6 x^{2} + 1

Solution steps

\frac{d}{d x} (2 x^{3} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) + \frac{d x}{d x}

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d x}{d x} = 1

= 6 x^{2} + 1

\frac{d y}{d x} + y^{7} x + 3 y = 0

y^{^{'}} = \frac{x e ^{x}}{2 y}

x \to 0 lim (sin (\frac{1}{2}))

\int \frac{9 x ^{2}}{x ^{3} + 8} d x

\int \frac{( x ^{2} - 8 )}{8 x} d x

What is the derivative of f(x)=2x^3+x ?
The derivative of f(x)=2x^3+x is 6x^2+1
What is the first derivative of f(x)=2x^3+x ?
The first derivative of f(x)=2x^3+x is 6x^2+1