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Popular >

tangent of y=x^2+x,(1,2)

Solution

tangent of

y = x^{2} + x, (1, 2)

Solution

y = 3 x - 1

Solution steps

Find the slope of

y = x^{2} + x : \frac{d y}{d x} = 2 x + 1

Compute the slope of

y = x^{2} + x

at

(1, 2) : m = 3

Find the line with slope m=

3

and passing through

(1, 2) : y = 3 x - 1

y = 3 x - 1

Popular Examples

tangent of f(x)=-3cos(x),\at x= pi/2 tangent of

f (x) = - 3 cos (x), at x = \frac{π}{2}

area x^2+12x,3x^2+10,1,4 area

x^{2} + 12 x, 3 x^{2} + 10, 1, 4

integral of 1/((y^2+z^2)^{3/2)}

\int \frac{1}{( y ^{2} + z ^{2} ) ^{\frac{3}{2}}} d y

y^{''}-4y^'+4y=3x^2+2xe^{2x}

y^{^{''}} - 4 y^{^{'}} + 4 y = 3 x^{2} + 2 x e^{2 x}

sum from n=9 to infinity of e^{3-2n}

n = 9 \sum \infty e^{3 - 2 n}

Frequently Asked Questions (FAQ)

What is the tangent of y=x^2+x,(1,2) ?
The tangent of y=x^2+x,(1,2) is y=3x-1