What is the tangent of f(x)=-3cos(x),\at x= pi/2 ?

The tangent of f(x)=-3cos(x),\at x= pi/2 is y=3x-(3pi)/2

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tangent of f(x)=-3cos(x),\at x= pi/2

tangent of

f (x) = - 3 cos (x), at x = \frac{π}{2}

y = 3 x - \frac{3 π}{2}

Solution steps

Find the tangent point:

(\frac{π}{2}, 0)

Find the slope of

f (x) = - 3 cos (x) : \frac{df ( x )}{d x} = 3 sin (x)

Compute the slope of

f (x) = - 3 cos (x)

x = \frac{π}{2} : m = 3

Find the line with slope m=

3

and passing through

(\frac{π}{2}, 0) : y = 3 x - \frac{3 π}{2}

y = 3 x - \frac{3 π}{2}

x^{2} + 12 x, 3 x^{2} + 10, 1, 4

\int \frac{1}{( y ^{2} + z ^{2} ) ^{\frac{3}{2}}} d y

y^{^{''}} - 4 y^{^{'}} + 4 y = 3 x^{2} + 2 x e^{2 x}

n = 9 \sum \infty e^{3 - 2 n}

\frac{1}{1 + x}

What is the tangent of f(x)=-3cos(x),\at x= pi/2 ?
The tangent of f(x)=-3cos(x),\at x= pi/2 is y=3x-(3pi)/2