What is inverse oflaplace 1/(1+x) ?

The answer to inverse oflaplace 1/(1+x) is e^{-t}

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inverse oflaplace 1/(1+x)

inverse laplace

\frac{1}{1 + x}

e^{- t}

Solution steps

L^{- 1} {\frac{1}{1 + x}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{x + 1}} = e^{- t}

= e^{- t}

\int 5 x - 3 d x

x \to 0 lim (e^{π (x + 1)})

y^{^{'}} = 2 x y^{2} + 3 x^{2} y^{2}

x \to - 7 lim (\frac{1}{x ^{2} ( x + 7 )})

x^{^{''}} + x = e^{2 t}

What is inverse oflaplace 1/(1+x) ?
The answer to inverse oflaplace 1/(1+x) is e^{-t}