What is (\partial)/(\partial x)(y^3sin(3x)) ?

The answer to (\partial)/(\partial x)(y^3sin(3x)) is y^3cos(3x)*3

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(\partial)/(\partial x)(y^3sin(3x))

\frac{\partial}{\partial x} (y^{3} sin (3 x))

y^{3} cos (3 x) \cdot 3

Solution steps

\frac{\partial}{\partial x} (y^{3} sin (3 x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{3} \frac{\partial}{\partial x} (sin (3 x))

Apply the chain rule:

cos (3 x) \frac{\partial}{\partial x} (3 x)

= cos (3 x) \frac{\partial}{\partial x} (3 x)

\frac{\partial}{\partial x} (3 x) = 3

= y^{3} cos (3 x) \cdot 3

g (x) = \frac{( π ^{2} )}{x ^{2} + 4 x}

\frac{d}{d x} (sec (x) - x)

y = x^{2} + 4 x - 11, (2, - 1)

f (x) = 1 + x, x = 0

\frac{d}{d x} (2 1 - x^{2})

What is (\partial)/(\partial x)(y^3sin(3x)) ?
The answer to (\partial)/(\partial x)(y^3sin(3x)) is y^3cos(3x)*3