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Popular >

derivative of 6cos(2x-e^{-x})

Solution

\frac{d}{d x} (6 cos (2 x) - e^{- x})

Solution

- 12 sin (2 x) + e^{- x}

Solution steps

\frac{d}{d x} (6 cos (2 x) - e^{- x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 cos (2 x)) - \frac{d}{d x} (e^{- x})

\frac{d}{d x} (6 cos (2 x)) = - 12 sin (2 x)

\frac{d}{d x} (e^{- x}) = - e^{- x}

= - 12 sin (2 x) - (- e^{- x})

Simplify

= - 12 sin (2 x) + e^{- x}

Popular Examples

tangent of f(x)=2x^3+7x^2-8x-3,\at x=-1 tangent of

f (x) = 2 x^{3} + 7 x^{2} - 8 x - 3, at x = - 1

limit as x approaches 1-of 1-x-[x]-[1-x]

x \to 1 - lim (1 - x - [x] - [1 - x])

limit as x approaches 4-of 1/((x-4)^2)

x \to 4 - lim (\frac{1}{( x - 4 ) ^{2}})

derivative of f(x)=x^{(7)}-3e^{(3x)}derivative of

f (x) = x^{(7)} - 3 e^{(3 x)}

limit as x approaches 0 of (1+4x)^{1/x}

x \to 0 lim ((1 + 4 x)^{\frac{1}{x}})

Frequently Asked Questions (FAQ)

What is the derivative of 6cos(2x-e^{-x}) ?
The derivative of 6cos(2x-e^{-x}) is -12sin(2x)+e^{-x}
What is the first derivative of 6cos(2x-e^{-x}) ?
The first derivative of 6cos(2x-e^{-x}) is -12sin(2x)+e^{-x}