What is the limit as x approaches 0 of (1+4x)^{1/x} ?

The limit as x approaches 0 of (1+4x)^{1/x} is e^4

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limit as x approaches 0 of (1+4x)^{1/x}

x \to 0 lim ((1 + 4 x)^{\frac{1}{x}})

e^{4}

Decimal Notation

54.59815 \dots

Solution steps

x \to 0 lim ((1 + 4 x)^{\frac{1}{x}})

Apply exponent rules

= x \to 0 lim (e^{\frac{1}{x} l n (1 + 4 x)})

Apply the Limit Chain Rule:

e^{4}

= e^{4}

2 y^{^{''}} + 3 y^{^{'}} - 2 y = 25 e^{- 2 x}

(- 2, - 1), (2, 4)

arctan (6 x^{2} - 1)

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What is the limit as x approaches 0 of (1+4x)^{1/x} ?
The limit as x approaches 0 of (1+4x)^{1/x} is e^4