What is the slope ofintercept (-2,-1),(2,4) ?

The slope ofintercept (-2,-1),(2,4) is y= 5/4 x+3/2

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slope ofintercept (-2,-1),(2,4)

slope intercept

(- 2, - 1), (2, 4)

y = \frac{5}{4} x + \frac{3}{2}

Solution steps

Compute the slope

(- 2, - 1), (2, 4) : m = \frac{5}{4}

Compute the

y

intercept:

b = \frac{3}{2}

Construct the line equation

y = mx + b

where

m = \frac{5}{4}

and

b = \frac{3}{2}

y = \frac{5}{4} x + \frac{3}{2}

arctan (6 x^{2} - 1)

\int 8 x \cdot csc^{2} (4 x) d x

\int 2^{5 x + 2} d x

2 x y^{^{'}} + y = 6 x, y (4) = 15

What is the slope ofintercept (-2,-1),(2,4) ?
The slope ofintercept (-2,-1),(2,4) is y= 5/4 x+3/2