What is the derivative of \sqrt[3]{2x-7} ?

The derivative of \sqrt[3]{2x-7} is 2/(3(2x-7)^{2/3)}

What is the first derivative of \sqrt[3]{2x-7} ?

The first derivative of \sqrt[3]{2x-7} is 2/(3(2x-7)^{2/3)}

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\frac{2}{3 ( 2 x - 7 ) ^{\frac{2}{3}}}

Solution steps

Apply the chain rule:

\frac{1}{3 ( 2 x - 7 ) ^{\frac{2}{3}}} \frac{d}{d x} (2 x - 7)

= \frac{1}{3 ( 2 x - 7 ) ^{\frac{2}{3}}} \frac{d}{d x} (2 x - 7)

\frac{d}{d x} (2 x - 7) = 2

= \frac{1}{3 ( 2 x - 7 ) ^{\frac{2}{3}}} \cdot 2

Simplify

\frac{1}{3 ( 2 x - 7 ) ^{\frac{2}{3}}} \cdot 2 : \frac{2}{3 ( 2 x - 7 ) ^{\frac{2}{3}}}

= \frac{2}{3 ( 2 x - 7 ) ^{\frac{2}{3}}}

\int \frac{x ^{'}}{x ^{2}} d x

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sin (\frac{2 π x}{33})

\frac{\partial}{\partial x} (6 x y + 5 yz + x z)

\frac{\partial}{\partial x} (2 x y - 3 x z^{2})

What is the derivative of \sqrt[3]{2x-7} ?
The derivative of \sqrt[3]{2x-7} is 2/(3(2x-7)^{2/3)}
What is the first derivative of \sqrt[3]{2x-7} ?
The first derivative of \sqrt[3]{2x-7} is 2/(3(2x-7)^{2/3)}