What is the integral of b/(sqrt(b^2-2b+2)) ?

The integral of b/(sqrt(b^2-2b+2)) is b/(sqrt(b^2-2b+2))x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of b/(sqrt(b^2-2b+2))

\int \frac{b}{b ^{2} - 2 b + 2}

\frac{b}{b ^{2} - 2 b + 2} x + C

Solution steps

\int \frac{b}{b ^{2} - 2 b + 2} d x

Integral of a constant:

\int a d x = a x

= \frac{b}{b ^{2} - 2 b + 2} x

Add a constant to the solution

= \frac{b}{b ^{2} - 2 b + 2} x + C

\int 3 x^{2} (x^{3} + 8)^{5} d x

y = - 2 sin (x^{2})

\int (2 x^{2} + 1) e^{x^{2}} d x

\int e^{6 t} cos (2 t) d t

\int_{0}^{2 π} 3 sin (2 t) d t

What is the integral of b/(sqrt(b^2-2b+2)) ?
The integral of b/(sqrt(b^2-2b+2)) is b/(sqrt(b^2-2b+2))x+C