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Popular >

y^'=1-y/(20)

Solution

y^{^{'}} = 1 - \frac{y}{20}

Solution

y = - e^{\frac{- t - c _{1}}{20}} + 20

Solution steps

y^{'} (t) = 1 - \frac{y}{20}

Solve separable ODE:

y = - e^{\frac{- t - c _{1}}{20}} + 20

y = - e^{\frac{- t - c _{1}}{20}} + 20

Popular Examples

7x^2y^'=y^'+9xe-y

7 x^{2} y^{^{'}} = y^{^{'}} + 9 x e - y

integral from 1 to infinity of 1/(x^2+x)

\int_{1}^{\infty} \frac{1}{x ^{2} + x} d x

derivative of 2^xln^2(2)

\frac{d}{d x} (2^{x} ln^{2} (2))

area 9x+11,7x+14,[23,13]area

9 x + 11, 7 x + 14, [23, 13]

(\partial)/(\partial y)(e^ysin(x))

\frac{\partial}{\partial y} (e^{y} sin (x))

Frequently Asked Questions (FAQ)

What is the solution for y^'=1-y/(20) ?
The solution for y^'=1-y/(20) is y=-e^{(-t-c_{1})/(20)}+20