What is the derivative of (x^3-2^2) ?

The derivative of (x^3-2^2) is 6x^2(x^3-2)

What is the first derivative of (x^3-2^2) ?

The first derivative of (x^3-2^2) is 6x^2(x^3-2)

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\frac{d}{d x} ((x^{3} - 2)^{2})

6 x^{2} (x^{3} - 2)

Solution steps

\frac{d}{d x} ((x^{3} - 2)^{2})

Apply the chain rule:

2 (x^{3} - 2) \frac{d}{d x} (x^{3} - 2)

= 2 (x^{3} - 2) \frac{d}{d x} (x^{3} - 2)

\frac{d}{d x} (x^{3} - 2) = 3 x^{2}

= 2 (x^{3} - 2) \cdot 3 x^{2}

Simplify

= 6 x^{2} (x^{3} - 2)

\int \frac{1}{e ^{- x} + e ^{x}} d x

t \to 0 + lim (\frac{4}{t} - \frac{1}{e ^{t} - 1})

\frac{d}{d x} (2 csc (x) cot (x))

y = 2 x + 1, at x = \frac{1}{4}

\frac{s ^{2}}{( s - 3 ) ( s ^{2} + 5 )}

What is the derivative of (x^3-2^2) ?
The derivative of (x^3-2^2) is 6x^2(x^3-2)
What is the first derivative of (x^3-2^2) ?
The first derivative of (x^3-2^2) is 6x^2(x^3-2)