What is the integral of (e^x)/(e^x+8) ?

The integral of (e^x)/(e^x+8) is ln|e^x+8|+C

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integral of (e^x)/(e^x+8)

\int \frac{e ^{x}}{e ^{x} + 8} d x

ln ∣ e^{x} + 8 ∣ + C

Solution steps

\int \frac{e ^{x}}{e ^{x} + 8} d x

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = e^{x} + 8

= ln ∣ e^{x} + 8 ∣

Add a constant to the solution

= ln ∣ e^{x} + 8 ∣ + C

\int_{0}^{1} \frac{4}{x ( 1 + x )} d x

θ \to 0 lim (\frac{2 sin ( 3 θ )}{θ})

\frac{d}{d x} (\frac{7}{x ln ( x )})

\frac{\partial}{\partial y} (x^{2} + z^{2})

\frac{\partial}{\partial x} (a)

What is the integral of (e^x)/(e^x+8) ?
The integral of (e^x)/(e^x+8) is ln|e^x+8|+C