What is the derivative of 2/(3x^3) ?

The derivative of 2/(3x^3) is -2/(x^4)

What is the first derivative of 2/(3x^3) ?

The first derivative of 2/(3x^3) is -2/(x^4)

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\frac{d}{d x} (\frac{2}{3 x ^{3}})

- \frac{2}{x ^{4}}

Solution steps

\frac{d}{d x} (\frac{2}{3 x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{2}{3} \frac{d}{d x} (\frac{1}{x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{2}{3} \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{2}{3} (- 3 x^{- 3 - 1})

Simplify

\frac{2}{3} (- 3 x^{- 3 - 1}) : - \frac{2}{x ^{4}}

= - \frac{2}{x ^{4}}

\int \frac{8}{x ^{7}} d x

\int 18 x^{17} d x

x + x + x

x^{2} y^{^{'}} + x y = 1

\frac{s}{( s ^{2} - 1 ^{2} ) ( s ^{2} + 17 )}

What is the derivative of 2/(3x^3) ?
The derivative of 2/(3x^3) is -2/(x^4)
What is the first derivative of 2/(3x^3) ?
The first derivative of 2/(3x^3) is -2/(x^4)