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Popular >

x^2y^'+xy=1

Solution

x^{2} y^{^{'}} + x y = 1

Solution

y = \frac{ln ( x )}{x} + \frac{c _{1}}{x}

Solution steps

x^{2} y^{'} (x) + x y = 1

Solve linear ODE:

y = \frac{ln ( x )}{x} + \frac{c _{1}}{x}

y = \frac{ln ( x )}{x} + \frac{c _{1}}{x}

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\int \frac{x + 10}{x ^{2} + 6 x + 13} d x

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(\partial)/(\partial x)(-x+y)

\frac{\partial}{\partial x} (- x + y)

Frequently Asked Questions (FAQ)

What is the solution for x^2y^'+xy=1 ?
The solution for x^2y^'+xy=1 is y=(ln(x))/x+(c_{1})/x