What is the solution for 5ty^'+(10+5t((2(t-7))/(7t)))y=0 ?

The solution for 5ty^'+(10+5t((2(t-7))/(7t)))y=0 is y=e^{(-2t-c_{1})/7}

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5ty^'+(10+5t((2(t-7))/(7t)))y=0

5 t y^{^{'}} + (10 + 5 t (\frac{2 ( t - 7 )}{7 t})) y = 0

y = e^{\frac{- 2 t - c _{1}}{7}}

Solution steps

5 t y^{'} (t) + (10 + 5 t (\frac{2 ( t - 7 )}{7 t})) y = 0

Solve separable ODE:

y = e^{\frac{- 2 t - c _{1}}{7}}

y = e^{\frac{- 2 t - c _{1}}{7}}

\frac{\partial}{\partial x} (10 sin (x y))

\int (12 x + 7) d x

x \to 4 lim (\frac{1}{x - 3})

- \frac{170 t}{( t + 4 ) ^{2}}

x \to 1 + lim (\frac{3}{1 - x})

What is the solution for 5ty^'+(10+5t((2(t-7))/(7t)))y=0 ?
The solution for 5ty^'+(10+5t((2(t-7))/(7t)))y=0 is y=e^{(-2t-c_{1})/7}