What is the derivative of ln(x+1) ?

The derivative of ln(x+1) is 1/(x+1)

What is the first derivative of ln(x+1) ?

The first derivative of ln(x+1) is 1/(x+1)

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derivative of

ln (x + 1)

\frac{1}{x + 1}

Solution steps

\frac{d}{d x} (ln (x + 1))

Apply the chain rule:

\frac{1}{x + 1} \frac{d}{d x} (x + 1)

= \frac{1}{x + 1} \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= \frac{1}{x + 1} \cdot 1

Simplify

= \frac{1}{x + 1}

\frac{d ^{3}}{d x ^{3}} (sin (7 x))

y^{^{''}} + 6 y^{^{'}} + 9 y = 0, y (1) = 0, y^{^{'}} (1) = 1

f (x) = 3 - x - x^{2}, at x = 1

\frac{d}{d x} (x^{3} + 4 x^{2} - 6 x + 1)

20 y^{^{''}} - 11 y^{^{'}} - 3 y = 0

What is the derivative of ln(x+1) ?
The derivative of ln(x+1) is 1/(x+1)
What is the first derivative of ln(x+1) ?
The first derivative of ln(x+1) is 1/(x+1)