What is the integral from 2 to infinity of 9/(x^2) ?

The integral from 2 to infinity of 9/(x^2) is 9/2

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integral from 2 to infinity of 9/(x^2)

\int_{2}^{\infty} \frac{9}{x ^{2}} d x

\frac{9}{2}

Decimal Notation

4.5

Solution steps

\int_{2}^{\infty} \frac{9}{x ^{2}} d x

Compute the indefinite integral:

\int \frac{9}{x ^{2}} d x = - \frac{9}{x} + C

Compute the boundaries:

\int_{2}^{\infty} \frac{9}{x ^{2}} d x = 0 - (- \frac{9}{2})

= 0 - (- \frac{9}{2})

Simplify

= \frac{9}{2}

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\frac{x - 7}{- 5 x - 10}

\frac{d}{d x} (x^{n} ln (x))

What is the integral from 2 to infinity of 9/(x^2) ?
The integral from 2 to infinity of 9/(x^2) is 9/2