What is (\partial)/(\partial x)(2xe^{-y}) ?

The answer to (\partial)/(\partial x)(2xe^{-y}) is 2e^{-y}

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(\partial)/(\partial x)(2xe^{-y})

\frac{\partial}{\partial x} (2 x e^{- y})

2 e^{- y}

Solution steps

\frac{\partial}{\partial x} (2 x e^{- y})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 e^{- y} \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= 2 e^{- y} \cdot 1

Simplify

= 2 e^{- y}

y^{^{'}} + 6 y = 60, y (1) = 60

\int \frac{1}{1 - tan ^{2} ( x )} d x

\frac{d y}{d x} = \frac{x + y + 2}{x + y - 4}

x \to 0 lim (x^{2} + 2)

\frac{d}{d x} (cos (2 x) 2)

What is (\partial)/(\partial x)(2xe^{-y}) ?
The answer to (\partial)/(\partial x)(2xe^{-y}) is 2e^{-y}