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Popular >

tangent of y=x^2+2,(1,3)

Solution

tangent of

y = x^{2} + 2, (1, 3)

Solution

y = 2 x + 1

Solution steps

Find the slope of

y = x^{2} + 2 : \frac{d y}{d x} = 2 x

Compute the slope of

y = x^{2} + 2

at

(1, 3) : m = 2

Find the line with slope m=

2

and passing through

(1, 3) : y = 2 x + 1

y = 2 x + 1

Popular Examples

integral of (\sqrt[5]{x}+\sqrt[6]{x})

limit as x approaches 0 of 1/(x^2(x-7))

x \to 0 lim (\frac{1}{x ^{2} ( x - 7 )})

derivative of ln(y+y^2+cos(x))

\frac{d}{d x} (ln (y) + y^{2} + cos (x))

y^{''}+2y^'+y=sin(2t)

y^{^{''}} + 2 y^{^{'}} + y = sin (2 t)

integral from-infinity to 6 of xe^{x/2}

\int_{- \infty}^{6} x e^{\frac{x}{2}} d x

Frequently Asked Questions (FAQ)

What is the tangent of y=x^2+2,(1,3) ?
The tangent of y=x^2+2,(1,3) is y=2x+1