What is the limit as x approaches 2 of e^{1/0} ?

The limit as x approaches 2 of e^{1/0} is Does not exist

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limit as x approaches 2 of e^{1/0}

x \to 2 lim (e^{\frac{1}{0}})

Does not exist

Solution steps

x \to 2 lim (e^{\frac{1}{0}})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 2 - lim (e^{\frac{1}{0}}) =

Does not exist

x \to 2 + lim (e^{\frac{1}{0}}) =

Does not exist

= Does not exist

y = 3 tan (x), at x = \frac{π}{6}

\int 8^{3} x d x

y^{^{'}} - \frac{6}{x} y = \frac{y ^{5}}{x ^{7}}

\int \frac{1}{x ^{2} - 2 x + 17} d x

x \to 0 lim (ln (x^{2}))

What is the limit as x approaches 2 of e^{1/0} ?
The limit as x approaches 2 of e^{1/0} is Does not exist