What is the integral from 1 to 2 of (4x-2/(x^2)) ?

The integral from 1 to 2 of (4x-2/(x^2)) is 5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 2 of (4x-2/(x^2))

\int_{1}^{2} (4 x - \frac{2}{x ^{2}}) d x

5

Solution steps

\int_{1}^{2} 4 x - \frac{2}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 4 x d x - \int_{1}^{2} \frac{2}{x ^{2}} d x

\int_{1}^{2} 4 x d x = 6

\int_{1}^{2} \frac{2}{x ^{2}} d x = 1

= 6 - 1

Simplify

= 5

\int sec^{7} (4 x) tan (4 x) d x

f (x) = \frac{10}{x}

\frac{d}{d x} (524288 sin (2 x))

\frac{1}{2 x ^{4}}

\int_{2}^{3} \frac{37}{3 - x} d x

What is the integral from 1 to 2 of (4x-2/(x^2)) ?
The integral from 1 to 2 of (4x-2/(x^2)) is 5