What is the integral from-2 to 1 of (8x^3-3x^2) ?

The integral from-2 to 1 of (8x^3-3x^2) is -39

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-2 to 1 of (8x^3-3x^2)

\int_{- 2}^{1} (8 x^{3} - 3 x^{2}) d x

- 39

Solution steps

\int_{- 2}^{1} 8 x^{3} - 3 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{1} 8 x^{3} d x - \int_{- 2}^{1} 3 x^{2} d x

\int_{- 2}^{1} 8 x^{3} d x = - 30

\int_{- 2}^{1} 3 x^{2} d x = 9

= - 30 - 9

Simplify

= - 39

\frac{d y}{d x} = 3 x e^{y}

\frac{d}{d x} (- \frac{1}{2} cos (x))

(7 - 6 x)^{\frac{1}{2}}, at x = - 1

\int_{1}^{2} \frac{1}{x ^{3}} d x

f (x) = x^{2} + x, (2, 6)

What is the integral from-2 to 1 of (8x^3-3x^2) ?
The integral from-2 to 1 of (8x^3-3x^2) is -39