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Popular >

d/(dt)(sqrt(6/5-t^2))

Solution

\frac{d}{d t} (\frac{6}{5} - t^{2})

Solution

- \frac{5 t}{6 - 5 t ^{2}}

Solution steps

\frac{d}{d t} (\frac{6}{5} - t^{2})

Apply the chain rule:

\frac{1}{2 \frac{6}{5} - t ^{2}} \frac{d}{d t} (\frac{6}{5} - t^{2})

= \frac{1}{2 \frac{6}{5} - t ^{2}} \frac{d}{d t} (\frac{6}{5} - t^{2})

\frac{d}{d t} (\frac{6}{5} - t^{2}) = - 2 t

= \frac{1}{2 \frac{6}{5} - t ^{2}} (- 2 t)

Simplify

\frac{1}{2 \frac{6}{5} - t ^{2}} (- 2 t) : - \frac{5 t}{6 - 5 t ^{2}}

= - \frac{5 t}{6 - 5 t ^{2}}

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n = 1 \sum \infty n! x^{n}

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\frac{d}{d y} (x y 1 - \frac{x ^{2}}{4} - \frac{y ^{2}}{9})

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\int \frac{5 x ^{2} + 3 x - 1}{x ^{3} - 2 x ^{2} + x - 2} d x

limit as x approaches 0 of (x^2-3x)/(2x)

x \to 0 lim (\frac{x ^{2} - 3 x}{2 x})

Frequently Asked Questions (FAQ)

What is the d/(dt)(sqrt(6/5-t^2)) ?
The d/(dt)(sqrt(6/5-t^2)) is -(sqrt(5)t)/(sqrt(6-5t^2))
What is the first d/(dt)(sqrt(6/5-t^2)) ?
The first d/(dt)(sqrt(6/5-t^2)) is -(sqrt(5)t)/(sqrt(6-5t^2))