What is the tangent of 2/(x^2) ?

The tangent of 2/(x^2) is y=-4/(a_{0)^3}x+6/(a_{0)^2}

Popular >

tangent of 2/(x^2)

tangent of

\frac{2}{x ^{2}}

y = - \frac{4}{a _{0}^{3}} x + \frac{6}{a _{0}^{2}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{2}{a _{0}^{2}})

Find the slope of

y = \frac{2}{x ^{2}} : \frac{d y}{d x} = - \frac{4}{x ^{3}}

Compute the slope of

y = \frac{2}{x ^{2}}

x = a_{0} : m = - \frac{4}{a _{0}^{3}}

Find the line with slope m=

- \frac{4}{a _{0}^{3}}

and passing through

(a_{0}, \frac{2}{a _{0}^{2}}) : y = - \frac{4}{a _{0}^{3}} x + \frac{6}{a _{0}^{2}}

y = - \frac{4}{a _{0}^{3}} x + \frac{6}{a _{0}^{2}}

\frac{d}{d x} (ln ((x^{2})^{2}))

(- π, 0), (- \frac{π}{2}, 4)

\frac{2}{y}

\int \frac{x ^{2} - 2}{2 x} d x

\frac{\partial}{\partial x} (\frac{7 x - 5 y}{y ^{2} + 2 x ^{2}})

What is the tangent of 2/(x^2) ?
The tangent of 2/(x^2) is y=-4/(a_{0)^3}x+6/(a_{0)^2}