What is the integral of 6/7 x^{-1/7} ?

The integral of 6/7 x^{-1/7} is x^{6/7}+C

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integral of 6/7 x^{-1/7}

\int \frac{6}{7} x^{- \frac{1}{7}} d x

x^{\frac{6}{7}} + C

Solution steps

\int \frac{6}{7} x^{- \frac{1}{7}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{6}{7} \cdot \int x^{- \frac{1}{7}} d x

Apply the Power Rule

: \frac{7}{6} x^{\frac{6}{7}}

= \frac{6}{7} \cdot \frac{7}{6} x^{\frac{6}{7}}

Simplify

\frac{6}{7} \cdot \frac{7}{6} x^{\frac{6}{7}} : x^{\frac{6}{7}}

= x^{\frac{6}{7}}

Add a constant to the solution

= x^{\frac{6}{7}} + C

x \to 3 - lim ((x - 3)^{- 1})

\frac{\partial}{\partial y} (ln (10 x^{2} - 7 y^{2}))

f (x) = \frac{4 - 3 x - x ^{2}}{x ^{2} - 1}

\int 10 arcsin (x) d x

What is the integral of 6/7 x^{-1/7} ?
The integral of 6/7 x^{-1/7} is x^{6/7}+C