What is the tangent of 2/(3\sqrt[3]{x)} ?

The tangent of 2/(3\sqrt[3]{x)} is y=-2/(9a_{0)^{4/3}}x+8/(9\sqrt[3]{a_{0)}}

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tangent of 2/(3\sqrt[3]{x)}

tangent of

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

Find the slope of

Compute the slope of

x = a_{0} : m = - \frac{2}{9 a _{0}^{\frac{4}{3}}}

Find the line with slope m=

- \frac{2}{9 a _{0}^{\frac{4}{3}}}

and passing through

f (x) = \frac{4 - 3 x - x ^{2}}{x ^{2} - 1}

\int 10 arcsin (x) d x

x \to - 2 lim ((x + 1) (x + 3))

x^{(\frac{2}{x})}

y = 3 x^{2} + 12 x + 6

What is the tangent of 2/(3\sqrt[3]{x)} ?
The tangent of 2/(3\sqrt[3]{x)} is y=-2/(9a_{0)^{4/3}}x+8/(9\sqrt[3]{a_{0)}}