What is the solution for y=(2y^4+2x)(dy)/(dx) ?

The solution for y=(2y^4+2x)(dy)/(dx) is

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y=(2y^4+2x)(dy)/(dx)

y = (2 y^{4} + 2 x) \frac{d y}{d x}

y = - \frac{c _{1} + c _{1}^{2} + 4 x}{2}, y = - - \frac{c _{1} + c _{1}^{2} + 4 x}{2}, y = - \frac{c _{1} - c _{1}^{2} + 4 x}{2}, y = - - \frac{c _{1} - c _{1}^{2} + 4 x}{2}

Solution steps

y = (2 y^{4} + 2 x) \frac{d y}{d x}

Solve exact ODE:

y = - \frac{c _{1} + c _{1}^{2} + 4 x}{2}, y = - - \frac{c _{1} + c _{1}^{2} + 4 x}{2}, y = - \frac{c _{1} - c _{1}^{2} + 4 x}{2}, y = - - \frac{c _{1} - c _{1}^{2} + 4 x}{2}

y = - \frac{c _{1} + c _{1}^{2} + 4 x}{2}, y = - - \frac{c _{1} + c _{1}^{2} + 4 x}{2}, y = - \frac{c _{1} - c _{1}^{2} + 4 x}{2}, y = - - \frac{c _{1} - c _{1}^{2} + 4 x}{2}

\int_{0}^{\frac{π}{4}} \frac{1}{cos ( x )} d x

\frac{\partial}{\partial x} (cos (x^{3}))

\frac{d}{d x} (cos (x^{2}) \cdot 2 x)

\frac{\partial}{\partial x} (x e^{y} - 1)

x^{2} + y^{2} = 27

What is the solution for y=(2y^4+2x)(dy)/(dx) ?
The solution for y=(2y^4+2x)(dy)/(dx) is