What is the limit as x approaches 0 of (sin(40))/x ?

The limit as x approaches 0 of (sin(40))/x is diverges

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limit as x approaches 0 of (sin(40))/x

x \to 0 lim (\frac{sin ( 40 )}{x})

diverges

Solution steps

x \to 0 lim (\frac{sin ( 40 )}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{sin ( 40 )}{x}) = \infty

x \to 0 - lim (\frac{sin ( 40 )}{x}) = - \infty

= diverges

f (x) = \frac{3}{x + 3}

\int cos (5 x) cos (7 x) d x

\int_{0}^{3} - x^{2} + 9 d x

y^{^{'}} = \frac{( y ^{2} - 1 )}{2 x}, y (1) = - 2

\frac{d y}{d t} = - \frac{3 y}{t} - 2 - t^{- 4}, y (1) = 4

What is the limit as x approaches 0 of (sin(40))/x ?
The limit as x approaches 0 of (sin(40))/x is diverges