What is the tangent of f(x)=sqrt(x+5),(11,4) ?

The tangent of f(x)=sqrt(x+5),(11,4) is y= 1/8 x+21/8

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tangent of f(x)=sqrt(x+5),(11,4)

tangent of

f (x) = x + 5, (11, 4)

y = \frac{1}{8} x + \frac{21}{8}

Solution steps

Find the slope of

f (x) = x + 5 : \frac{df ( x )}{d x} = \frac{1}{2 x + 5}

Compute the slope of

f (x) = x + 5

(11, 4) : m = \frac{1}{8}

Find the line with slope m=

\frac{1}{8}

and passing through

(11, 4) : y = \frac{1}{8} x + \frac{21}{8}

y = \frac{1}{8} x + \frac{21}{8}

h (t) = (t + 2)^{\frac{2}{3}} (2 t^{2} - 3)^{3}

\frac{d}{d x} (\frac{e ^{3 x} + e ^{- 3 x}}{x})

\frac{d y}{d t} = (- csc (t) cot (t)) e^{- c s c (t)}

x \to \infty lim (- 3 x^{3})

x \to 0 - lim (1 - x^{2})

What is the tangent of f(x)=sqrt(x+5),(11,4) ?
The tangent of f(x)=sqrt(x+5),(11,4) is y= 1/8 x+21/8